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Lubov Fominskaja [6]
3 years ago
7

BRAINLIEST pleae help!!!

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0

I had a whole answer and my tab crashed.  Hate that.

We'll use the known sum of the first n natural numbers,

\displaystyle \sum_{k=1}^{n} k = \dfrac{n(n+1)}{2}

Let a be the first number, the one we seek.

\displaystyle 3^9= \sum_{k=0}^{26} (a+2k) = 27a+ 2 \sum_{k=1}^{26}k

\displaystyle 3^9=27a+2(26)(26+1)/2

3^9=27(a+26)

3^6= a+ 26

a = 3^6 - 26

a = 703 \quad\checkmark

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Find out more at: brainly.com/question/20418815

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