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3 years ago

Write 2/5 and 1/3as equivalent fractions using a common denominator

Mathematics

1 answer:

horrorfan [7]3 years ago

6 0

Answer:15

Step-by-step explanation:5 and 3 both go into 15

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Evaluate i^31 please help

Nadya [2.5K]

ANSWER

${i}^{31} = - i$

EXPLANATION

We want to evaluate

${i}^{31}$

Use indices to rewrite the expression as:

$= {i}^{30} \times i$

We know that

${i}^{2} = - 1$

So we rewrite the expression to obtain;

$= ({ {i}^{2}) }^{15} \times i$

This gives us;

$= {( - 1) }^{15} \times i$

This simplifies to

$= - 1 \times i$

$= - i$

4 0

3 years ago

Write and equation in slope intercept form of a line that has a slope of 1/3 and passes through the point (6,0)

ladessa [460]

y=(1/3)x-2

Step-by-step explanation:

the slope-intercept form is y-y1=m(x-x1)

hence, y-0=1/3(x-6) or y=(1/3)x-2

3 0

2 years ago

If a person measures 42in in height what does the person measure in feet. I got the answer correct which is 3ft 6in but I need t

faust18 [17]

$42in=42\cdot0.0833333ft=3.5ft\\\\Answetr\ is\ 3.5\ feet.$

6 0

3 years ago

Read 2 more answers

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

A canadian goose and a Great blue heron took off in opposite directions. The goose flew at 20 mph, and the heron flew at 10 mph.

iris [78.8K]

The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let a represent the time flown by the goose and b represent the time flown by the heron. Hence:

a + b = 14 (1)

Also:

20a + 10b = 180 (2)

From equation 1 and 2:

a = 4, b = 10

The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0

1 year ago