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3 years ago

Find the length of arc RQ. Use 3.14

Mathematics

1 answer:

Helen [10]3 years ago

7 0

Answer:

The length of arc PQ is 8.1 inches.

Step-by-step explanation:

First, you have to find the angle of POQ. Given that total angles in a circle is 360°, so you have to subtract to get ∠POQ :

$73 + 150 + 65 + ∠POQ = 360$

$288 + ∠POQ = 360$

$∠POQ = 360 - 288 = 72$

Next, you have to apply length of arc formula, Arc = θ/360×2×π×r where θ represents the angle of arc and r is the radius of circle :

$arc = \frac{θ}{360} \times 2 \times \pi \times r$

$let \: θ = 72,\pi = 3.14,r = 6.48$

$arc = \frac{72}{360} \times 2 \times 3.14 \times 6.48$

$arc = 8.1 \: inches \: (near.tenth)$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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oksian1 [2.3K]

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3 years ago

1. Solve proportion 12/15 = 18/b

omeli [17]

We solve the as follows:

1. Solve proportion 12/15 = 18/b
( 12/15 = 18/b ) b
( 12b/15 = 18 ) 15/12
b = 18(15/12)
b = 45/2

2. Solve equations

A. -x + 4 = x +6
-x + 4 - x = x +6 - x
-2x + 4 - 4 = 6 - 4
-2x = 2
x = -1

B. 5n + 7 =7(n+1) -2n
5n + 7 = 7n + 7 - 2n
5n -7n + 2n = 7 - 7
0 = 0

C. -4(p+2) + 8 = 2(p-1) - 7p + 15
-4p - 8 + 8 = 2p - 2 - 7p + 15
-4p + 7p - 2p = -2 + 15 + 8 - 8
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3. Solve a/b x - c = 0 for x
a/b x - c = 0
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3 years ago

How do you do series with an n

SOVA2 [1]

The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.
$\sum{a+b}=\sum{a}+\sum{b}$
$\sum{kx}=k\sum{x}$
$\sum_{r=1}^n{1}=n$
$\sum_{r=1}^n{r}=n(n+1)/2$

Armed with the above rules, we can split up the summation into simple terms:
$\sum_{r=1}^n{40r-21n+8}=n$
$=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}$
$=40\frac{n(n+1)}{2}-21n^2+8n$
$=20n(n+1)-21n^2+8n$
$=28n-n^2$

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196

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2 years ago