Eight children are divided into two teams each containing 4 children. how many different divisions are possible?
1 answer:
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Answer:
235 cm²
Step-by-step explanation:
Find area of the large rectangle on the bottom. To do that, find its length and width, then multiply them together.
Length of big rectangle=20 cm
Width of big rectangle=9 cm
20x9=180 cm²
Next, find the area of the small rectangle on the top. To do that, find its length and width, then multiply them together.
Length of small rectangle=11 cm
Width of small rectangle=5 cm
I found the width by subtracting 9 from 14, since the 9 cm is part of the large rectangle.
11x5=55 cm²
Add the areas of the two rectangles.
55+180=235 cm²
Answer:
21,500
Step-by-step explanation:
Given data ( in thousand ) in this year,
28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,
If each data is increased by $ 3000 in the next year,
So, the data for the next year,
31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,
Since, the data is already arranged in the ascending order,
The median is 51 which is between 50 and 52,
Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,
Having median =
= 42,
Upper half of the data is 52 54 55 55 63 64 70 75 78 80,
Having median = 63.5
Hence, the interquartile range =
= 63.5 - 42
= 21.5
That is, the Interquartile range would be 21, 500.