Answer:
Step-by-step explanation:
This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).
350000 passengers
(350000 passengers) * 1
(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)
[note: passengers and carriages cancel. Leaving only trains]
(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]
729.1667 trains [oh, but don’t just round this number either up or down]
729 full trains can carry 729*32*15 = 349920 passengers
730 full trains can carry 730*32*15 = 350400 passengers
Now, we can say that 730 trains are adequate to carry 350000 passengers.
∠3 = ∠6 = 46°
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Do (7x3)=21x7=147 so that’s how you do it hope it helps
![\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32](https://tex.z-dn.net/?f=%20%5Cleft%28%20%5Cdfrac%201%20%7B64%7D%20%5Cright%29%5E%7B-%205%2F6%7D%20%3D64%5E%7B5%2F6%7D%20%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%5E5%20%3D%202%5E5%20%3D32)
TRUE
![\sqrt[5]{36^4}=36^{4/5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B36%5E4%7D%3D36%5E%7B4%2F5%7D)
which surely isn't 36. FALSE
FALSE
For the fourth one we have a
which isnt
so this is FALSE.
No fractions in that one so FALSE.
