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3 years ago

A number that is equal to 36 more than y

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

5 Hope I helped. Have a good day

nikklg [1K]3 years ago

6 0

Solution:

we have been asked to write the expression for

A number that is equal to 36 more than y.

Here as we can see the resulting number is being compared with y.

And when the number is being copared with y, it was found that its greater by 36.

If the required number be N, Then we can write ,

$N=36+y$

Hence the required number is $N=36+y$

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The third term of the sequence is 120. The fifth term is 76.8 The explicit rule for the geometric sequence is an=?(?)n-1

gulaghasi [49]

Answer:

The explicit rule of the geometric sequence

aₙ = 187.5 (0.8)ⁿ⁻¹

Step-by-step explanation:

Step(i):-

Given that the third term of the sequence = 120

tₙ = a rⁿ⁻¹

t₃ = a r³⁻¹ = ar²

120 = ar² ..(i)

Given that the fifth term of the given geometric sequence = 76.8

tₙ = a rⁿ⁻¹

t₅ = a r⁵⁻¹ = a r⁴

76.8 = a r⁴...(ii)

Step(ii):-

Dividing (ii) and (i)

$\frac{ar^{4} }{ar^{2} } = \frac{76.8}{120}$

r² = 0.64

r =√ 0.64 = 0.8

Substitute r= 0.8 in equation (i)

120 = ar²

120 = a(0.8)²

⇒ $a = \frac{120}{0.64} =187.5$

Step(iii):-

The explicit rule of the geometric sequence

aₙ = a rⁿ⁻¹

put a= 187.5 and r = 0.8

aₙ = 187.5 (0.8)ⁿ⁻¹

7 0

2 years ago

Which of the following statements is true?

ra1l [238]

Ur answer is B............!!!!!!

Hope its right!!

7 0

3 years ago

Read 2 more answers

Write an equation reprezeting x axis

Rudiy27

Answer:

y=0

Step-by-step explanation:

All y-values along the x-axis are equal to 0.

3 0

3 years ago

ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!

posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 y ², radius y, and thickness ∆y, thus contributing an area of 2π y (3 - 3/4 y ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ y ≤ 2, thus given by the integral

$\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi$

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 x), thus contributing an area of π (√(4/3 x))² = 4π/3 x. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ x ≤ 3, or by the integral

$\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi$

Using either method, the volume is 6π ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0

3 years ago

Which of the following choices

Lapatulllka [165]

Answer:

Denote AH as height of triangle ABC, with H lies on BC.

Applying sine theorem:

AH/AC = sin 60

=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7

=> Area of triangle ABC is calculated by:

A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611

=> Option C is correct.

Hope this helps!

3 0

3 years ago