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Ray Of Light [21]
3 years ago
6

Find measure of side AB round to nearest tenth

Mathematics
1 answer:
vova2212 [387]3 years ago
8 0
Use:

|AB|^2=|AC|^2+|BC|^2-2|AC||BC|\cos(m\angle ACB)

We have:

|AC|=13;\ |BC|=29;\ m\angle ACB=41^o

\cos41^o\approx0.7547

substitute:

|AB|^2=13^2+29^6-2\cdot13\cdot29\cdot0.7547\\\\|AB|^2=440.9562\\\\|AB|\approx21
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