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shutvik [7]
3 years ago
14

HELPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

SAS

Step-by-step explanation:

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skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
The diameter of the dot produced by a printer is normally distributed with a mean diameter of 0.002 inch. Suppose that the speci
Leni [432]

Answer:

0.0002 inch

Step-by-step explanation:

The empirical rule of the normal distribution, the 68-95-99.7 rule, means

if the mean is <em>μ</em> and the standard deviation is <em>σ</em>,

68% of data lies within <em>μ </em>- <em>σ</em> and <em>μ </em>+ <em>σ</em>,

95% of data lies within <em>μ </em>- 2<em>σ</em> and <em>μ </em>+ 2<em>σ</em>,

99.7% of data lies within <em>μ </em>- 3<em>σ</em> and <em>μ </em>+ 3<em>σ.</em>

<em />

From the question, <em>μ</em> = 0.002.

The required range is 0.0014 to 0.0026.

With a probability of 0.9963, then 0.9963 × 100% = 99.63% should lie within the range. This approximately corresponds to <em>μ </em>- 3<em>σ</em> and <em>μ </em>+ 3<em>σ.</em>

<em>μ </em>- 3<em>σ</em> = 0.0014

0.002 - 3<em>σ</em> = 0.0014

3<em>σ</em> = 0.0006

<em>σ</em> = 0.0002

Hence, the standard deviation is 0.0002 inch

We can check with the other end of the range:

<em>μ </em>+ 3<em>σ</em> = 0.0026

3<em>σ</em> = 0.0026 - 0.002

3<em>σ</em> = 0.0006

<em>σ</em> = 0.0002

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