Note that

in the given closed interval, so the area is exactly given by the definite integral

(no absolute values needed!)
Integrating gives
Answer:
True
Step-by-step explanation:
Given that a function is

We are to find the slant asymptote if any for this function
Since numerator is of degree 2 and denominator 1, let us divide and then check
Doing long division we find
![f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D-%5Cfrac%7B11%7D%7B4%282x-3%29%7D)
Thus we find the asymptote y= the quotient obtained i.e
![\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D%5C%5C%3D%5Cfrac%7Bx%7D%7B2%7D%20-%5Cfrac%7B5%7D%7B4%7D)
Hence asymptote is

Statement given is true.
N^2-3n-4=0
(n-4)(n+1)
-4+1=-3
-4*1=-4
n-4=0
n=4
n+1=0
n=-1
Final answers: x=-1, x=4
Use Picture Math, i cant type in the other cause brainly doesn't accept it but it is Ga_thMath. (u)
The answer is C
The reason being these two sets of angles are opposite angles (also known as vertical angles) and opposite angles are always congruent.