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just olya [345]
3 years ago
6

the area of a circle is 60 π sq.cm. find the radius of the radius of the circle to the nearest tenth step-by-step

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:

r = 7.7

Step-by-step explanation:

A = πr²

60π = πr²

r² = 60π/π

r² = 60

\sqrt{r^2} =\sqrt{60}

r = 7.746

Rounded to tenths:

7.7

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What is the solution of the following equation 2x^2-3x+2=0
zaharov [31]

Answer:

x= \frac{3+\sqrt{7}i}{4}} or x=\frac{3-\sqrt{7}i}{4}}

Step-by-step explanation:

2x^2-3x+2=0

We complete the square as follows

Group the constant term on the right hand side

2x^2-3x=-2

Divide through by 2,

x^2-\frac{3}{2}x=-1

Add half the square of the coefficient of x to get;

x^2-\frac{3}{2}x+(-\frac{3}{4})^2=-1+(-\frac{3}{4})^2

Simplify to get

(x-\frac{3}{4})^2=-1+\frac{9}{16}


(x-\frac{3}{4})^2=-\frac{7}{16}

Take the square root of both sides to get

(x-\frac{3}{4})=\pm \sqrt{-\frac{7}{16}}

Solve for x

(x-\frac{3}{4})=\pm \frac{\sqrt{7}i}{4}}


x=\frac{3}{4} \pm \frac{\sqrt{7}i}{4}}


x= \frac{3+\sqrt{7}i}{4}} or x=\frac{3-\sqrt{7}i}{4}}








6 0
3 years ago
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