Question

Simplify the expression. 3y3 – 2y[4y – y(y – 3)] – [2y(y + 1) – 3y(y2 –1)]

Answer 1

The first step for solving this expression is to distribute -y through the parenthesis.
3y³ - 2y × (4y - y² + 3y) - (2y × (y + 1) - 3y × (y² - 1))
Distribute 2y through the parenthesis.
3y³ - 2y × (4y - y² + 3y) - (2y² + 2y - 3y × (y² - 1))
Now distribute -3y through the parenthesis.
3y³ - 2y × (4y - y² + 3y) - (2y² + 2y - 3y³ + 3y)
Collect the like terms in the first set of the parenthesis.
3y³ - 2y × (7y - y²) - (2y² + 2y - 3y³ + 3y)
Collect the like terms in the second set of the parenthesis.
3y³ - 2y × (7y - y²) - (2y² + 5y - 3y³)
Distribute -2y through the parenthesis.
3y³ - 14y² + 2y³ - (2y² + 5y - 3y³)
Remember that when there is a "-" sign in front of the parenthesis,, you must change the sign of each term in the parenthesis. This will change the expression to the following:
3y³ - 14y² + 2y³ - 2y² - 5y + 3y³
Collect the like terms with an exponent of 3.
8y³ - 14y² - 2y² - 5y
Lastly,, collect like terms that have an exponent of 2.
8y³ - 16y² - 5y
Since we cannot simplify the expression any further,, the correct answer is going to be 8y³ - 16y² - 5y.
Let me know if you have any further questions.
:)