√52-√13+√117
sqrt (4*13) - sqrt (13) + sqrt (13*9)
sqrt(4)sqrt(13) -sqrt(13)+sqrt(13)sqrt(9)
2sqrt(13) -sqrt(13)+3sqt(13)
sqrt(13)[2-1+3]
4sqrt(13)
Choice A
Answer:
Haha there is no question
Step-by-step explanation:
Answer:
72÷6=12
so at the nursery it cost $12 per shrub
66÷6=11
so at the store it cost $11 per shrub
so if you buy 21 shrubs from the nursery it will cost: 12×21=$252
but if you buy 21 shrubs from the store it only cost: 11×21=$231
$252-$231=$21
Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)
so
the greatest number of lunch is 
Hence
the greatest number of dinner is 
therefore
the greatest number of meals is
<u>the answer is</u>
The coefficient of these two number are -24 and 7. :)
