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3 years ago

rashid is paid by the hour he earned 50 for a 4 hour workday how much does he earn for a 5 1/2 hour workday

Mathematics

1 answer:

gregori [183]3 years ago

7 0

Rashid is paid by the hour. He earned $50 for 4 hour workday. How much does he earn for a 5 1/2 hour workday?

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Use a proportion:

x/(5 1/2) = 50/4

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x = (11/2)(50/4)

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x = 550/8

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x = $68.75

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Carrie borrowed $960 in interest free to pay for a car repair. She will pay $120 monthly until the loan is paid off. How many mo

astraxan [27]

Answer:

It will take Carrie 8 months to pay off the loan

Step-by-step explanation:

Step 1: Determine the expression for total amount to be paid

T=m×n

where;

T=total amount to be payed

m=total payments per month

n=number of payments to be made

In our case;

T= $960

m= $120

n=unknown

replacing;

960=120×n

120 n=960

n=960/120

n=8 months

It will take Carrie 8 months to pay off the loan

6 0

3 years ago

What’s all input for f(x)=3

defon

Answer:

all inputs are equal to 3

Step-by-step explanation:

$f(x) = 3 \\ = 3 \times 1\\ = 3 \times {x}^{0} \\ anything \: raised \: to \: 0 \: is \: 1 \\$

$\\ substituting \: any \: value \\ \: of \: x \: in \: f(x) \\ f(3) = 3 \times {3}^{0} \\ = 3 \times 1 \\ = 3 \\$

$\\ similarly \: all \: values \: of \: x \: will \\ give \: 3$

8 0

3 years ago

Susie’s Sweet Shop sells chocolate boxes that contain three types of chocolate truffles: solid chocolate truffles, cream center

olganol [36]

Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.

6 0

3 years ago

A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter

Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

$x+y=15\operatorname{cm}$

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

$\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}$

We can now refine the equation as follow;

$\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}$

ANSWER:

The length of the shorter piece of wire is 6cm

7 0

1 year ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago