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EleoNora [17]
3 years ago
8

PLEASE HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

\frac{x^{2} + 19x + 102}{4(x + 5)(x + 7)}

Step-by-step explanation:

I have factored and multiplied lwh to get the volumes

Vol. = \frac{2x - 1}{(2x - 3)(x + 5)} \frac{2(2x - 3)}{3x - 1}\frac{(3x - 1)(x + 3)}{(2x - 1)(x + 3)} + \frac{x - 5}{3x + 2}\frac{3x + 2}{4}\frac{x - 2}{(x + 7)(x - 5)}

      = \frac{4}{x + 5} + \frac{x - 2}{4(x + 7)}

      = \frac{4(4)(x + 7) + (x - 2)(x + 5)}{4(x + 5)(x + 7)}

      =  \frac{16x + 112 + x^{2} + 3x -10}{4(x + 5)(x + 7)}

      = \frac{x^{2} + 19x + 102}{4(x + 5)(x + 7)}

If I have done everything correctly, then \frac{x^{2} + 19x + 102}{4(x + 5)(x + 7)} is the total volume

This a real exercise in factoring and multiplying and adding fractions

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You have $5600. The best interest rate you can find is 3%
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Answer:

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Step-by-step explanation:

The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by

A = P(1 + \frac{r}{n})^{nt}

Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03

We can rearrange the above equation to:

\frac{A}{P} = (1 + \frac{r}{n})^{nt}

Taking logs on both sides

log(\frac{A}{P}) = log(1 + \frac{r}{n})^{nt}

This gives

log(\frac{A}{P}) =nt \times log(1 + \frac{r}{n})\\So,\\nt = \frac{log(\frac{A}{P})}{ log(1 + \frac{r}{n})}

In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075

1 + r/n = 1+0.0075 = 1.0075

4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72

t = 72/4 = 18 years

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