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kramer
3 years ago
7

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

two decimal places.
the square side measures at 8in

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0
Let's start with the area of the square
area \: square = s \times s = 8 \times 8 = 64
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

area \: circle = \pi {r}^{2}  = \pi \times  {4}^{2}  = 16\pi
now we just subtract and our answer is

64 - 16\pi = 64 - 16 \times (3.14) = 13.73
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luda_lava [24]

Answer:

See the solution

Step-by-step explanation:

4 0
2 years ago
Lalo has five apples Tito took 3 apples how many apples dose lalo have ?
Gennadij [26K]
If Lalo has 5 apples and tito took 3 the answer is 2
6 0
2 years ago
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ou live in the building on the left in the drawing, and a friend lives in the other building. the two of you are having a discus
Alenkinab [10]

Answer:

1.3

Friend is wrong

Step-by-step explanation:

Given:

friend's claim: height of his building is more than 1.50 times the height of yours

line of sight to the top edge of the other building makes an angle of 21° above the horizontal

line of sight to the base of the other building makes an angle of 52° below the horizontal

Solution:

Let A be the height of your building is A

Let B+A his building is B higher than yours.

Let the distance between the buildings is x.  

then

tan 52 = A/x

tan 21 = B/x  

A/B = tan 52 / tan 21

      =  1.27994 / 0.38386

A/B = 3.33

(A + B) / A = 1.5 0

A/A + B/A = 1.50

1 + B/A = 1.50

B/A is basically (B/x) / (A/x)

So

1+ 3.33 / 3.33

= 4.33/3.33

= 1.3

Since 1.3 is not equal to 1.5

Hence the friend's claim is wrong.

5 0
3 years ago
write the equation of the line that passes through (2, 4) and has a slope of –1 in point-slope form. x – 4 = –1(y – 2) x – 2 = –
Kobotan [32]
The point-slope form: y-y_0=m(x-x_0)

m = -1; (2; 4) \to x_0=2;\ y_0=4

subtitute

y - 2 = -1(x - 4)
6 0
2 years ago
The derivative of (x^2 +1)(x^3+ 1) (by definition and basic rule)
dlinn [17]

Answer:

f'(x) = 5x^4 + 2x + 3x^2

Step-by-step explanation:

To find the derivative of this equation we can do two things.

One method is to use the product rule, which states that when f(x) consists of two functions multiplied to each other (meaning f(x) = g(x) * h(x)), the derivative is f'(x) = g'(x)*h(x) + g(x)*h'(x). In simple language, the derivative is found by finding the derivative of x² + 1 and multiplying it with the normal function of x³ + 1, after which you add the product of the nnormal function of x² + 1 and the derivative of x³ + 1.

it might be clearer when I show you:

f(x) = (x^2 + 1)(x^3 + 1)\\f'(x) = (2x)(x^3 + 1) + (x^2 + 1)(3x^2)\\Simplify:\\f'(x) = 2x^4 + 2x + 3x^4 + 3x^2 = 5x^4 + 3x^2 + 2x\\

If you are not familiar with this rule you can first write out the function and then use the basic rule:

f(x) = (x^2 +1)(x^3+1) = x^5 + x^2 + x^3 + 1\\f'(x) = 5x^4 + 2x + 3x^2

If you need any further help please say so in the comments! I hope this helps! If the steps seem complicated, I suggest you could revise expanding brackets (the first step of the second method) and the basic rules of deriving, but feel free to reach out if you struggle afterwards still

8 0
2 years ago
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