Write the equation in standard form for the circle x2+y2–2y–43=0.
2 answers:
The general equation of a circle is:
(x-a)²+(y-b)²=r², where a and b are the coordinates of the center, and r is the radius.
Now: x²+y²-2y-43=0
x²+y²-2y+1-44=0
Sqrt(44)=6.63, so we get:
Answer: x²+(y-1)²=6.63²
Answer:
x^2 + y(y - 2) = 43
Step-by-step explanation:
<u>Step 1: Add 43 to both sides</u>
x^2 + y^2 - 2y - 43 + 43 = 0 + 43
x^2 + y^2 - 2y = 43
<u>Step 2: Pull out the y from y^2 - 2y</u>
x^2 + y^2 - 2y = 43
x^2 + y(y - 2) = 43
Answer: x^2 + y(y - 2) = 43
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