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Ira Lisetskai [31]
3 years ago
8

Solve for s in terms of r, t, and u. r= -tus s=

Mathematics
2 answers:
Yuki888 [10]3 years ago
5 0

Answer:

Im pretty sure the answer is S=r/-tu

Step-by-step explanation:

You would divide -tu on both sides and it would cancel it on the right side of the equal sign. Then your left with s=r/-tu. Hoped this helped :)

julsineya [31]3 years ago
4 0

Answer:

s=\frac{r}{-tu}

Step-by-step explanation:

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Point c (2,2) is the center of the circle. what is the ratio of ac to the length of dc?
Nadya [2.5K]
They answer is 3::: (1:1)
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3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0
3 years ago
Easy work for extra points
melomori [17]
This ain’t easy for me
7 0
2 years ago
Read 2 more answers
Jill sold half of her comic books and then bought sixteen more. She now has 36. With how many did she begin?
Alex777 [14]

Answer:

\frac{1}{2}x + 16 = 36

40 comic books

Step-by-step explanation:

Let x be the Jill comic books.

Given:

Jill sold half of her comic books and then bought sixteen more. She now has 36.

\frac{1}{2}\ (Jill\ books) + 16\ more\ books = 36

\frac{1}{2}\ (x) + 16 = 36

\frac{1}{2}x + 16 = 36

Therefore the algebraic equation of the given statement.

\frac{1}{2}x + 16 = 36--------(1)

Now we solve above equation for x.

Subtract by 16 both side of the equation 1.

\frac{1}{2}x + 16 -16 = 36 -16

\frac{1}{2}x = 20

Multiply by 2 both side of the above equation.

2\times \frac{1}{2}x =2\times 20

x = 40

Therefore, Jill had 40 comic books.

8 0
3 years ago
Need Help ASAP<br><br> 1.5x+6=2+3x<br> 2.2(6-2y)=-1(4y-9) <br> 3.2z-6=2(z+2)+10
zavuch27 [327]
1. 5x + 6 = 2 + 3x
-3x. - 3x
-------------------------
2x + 6 = 2
- 6. - 6
-------------------------
2x = -4
---- -----
2. 2

x = -2

2. 2(6 -2y) = -1(4y-9)
12 -4y = -4y + 9
+4y. +4y
----------------------------
.12 /=\ 9
No solution

3. 2z-6 = 2(z+2) + 10
2z -6 = 2z + 4 + 10
2z -6 = 2z +14
-2z. -2z
-6 /=\ 14
No solution.
4 0
3 years ago
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