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Flura [38]
3 years ago
14

What is the solution to this system of equations

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0
The answer to the question is b

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There is a bag filled with 4 blue, 3 red and 5 green marbles.
zhannawk [14.2K]

Answer:

You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.

The probability of selecting a red marble the first time is 1313.

(This is because 4 out of 12 marbles are red and412412 reduces to 1313.

The probability of selecting a red marble the second time is 1313.

The marble selections are independent and you can multiply the two probabilities to get the following:

probability of getting 2 reds = (13)2(13)2

=19=19.

So the probability of getting two reds is 1919.

7 0
3 years ago
When we reject the null and the null is true, we have a made a _________ __________.
nydimaria [60]

When we reject the null and the null is true, we have a made a type I error

The null hypothesis in statistics states that there is no difference between groups or no relationship between variables. It is one of two mutually exclusive hypotheses about a population in a hypothesis test.

null hypothesis is denoted as H₀

Reject the null hypothesis when the p-value is less than or equal to your significance level. Your sample data favor the alternative hypothesis, which suggests that the effect exists in the population. When you can reject the null hypothesis, your results are statistically significant.

when the p-value is greater than your significance level, you fail to reject the null hypothesis.

Sometimes , we reject our null hypothesis even when its true

there we made a type I error in hypothesis

To know more about null hypothesis here

brainly.com/question/19263925

#SPJ4

3 0
1 year ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
kompoz [17]

Answer:

  5.9 years

Step-by-step explanation:

We believe a better representation of the compound interest formula is ...

  V(t)=P(1+\dfrac{r}{n})^{nt}

We want to find the value of t for P=1 and V(t)=2. We are told n=4, so the formula becomes ...

  2=(1+\dfrac{.12}{4})^{4t}\\\\\log{(2)}=4t\log{(1.03)}\quad\text{take logs}\\\\t=\dfrac{\log{2}}{4\log{1.03}}\approx\boxed{5.9\quad\text{years}}

8 0
4 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
kvasek [131]

Answer:

The answer is letter C) a cars distance at a constant speed

8 0
3 years ago
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