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Klio2033 [76]
3 years ago
5

Find the area of the irregular figure. Round to the nearest hundredth.

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

67.5\text{ [square units]}

Step-by-step explanation:

The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.

<u>Formulas</u>:

  • Area of rectangle with base b and height h: A=bh
  • Area of triangle with base b and height h: A=\frac{1}{2}bh

By definition, the base and height must intersect at a 90 degree angle.

The rectangle has a base of 10 and a height of 5. Therefore, its area is A=10\cdot 5=50.

The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is A=\frac{1}{2}\cdot 2\cdot 5=5.

Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is A=\frac{1}{2}\cdot 5\cdot 5=12.5.

Thus, the area of the total irregular figure is:

50+5+12.5=\boxed{67.5\text{ [square units]}}

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What is 7x+1-4+4+1+435
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Step-by-step explanation:

1) 7 is the only number with a variable, <em>x</em>, so it will remain as it is.

2) -4+4= 0

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2 years ago
An oil exploration company currently has two active projects, one in Asia and the other in Europe. Let A be the event that the A
Virty [35]

Answer:

a)

0.5

option A

b)

0.6

c)

0.1

Step-by-step explanation:

The event A and B are independent so

P(A∩B)=P(A)*P(B)

P(A∩B)=P(0.2)*P(0.5)=0.10

a)

We have to find P(B'|A')

P(B'|A')=P(B'∩A')/P(A')

P(A)=0.2

P(A')=Asian project is not successful=1-P(A)=1-0.2=0.8

P(B)=0.5

P(B')=Europe project is not successful=1-P(B)=1-0.5=0.5

P(B'∩A')=Europe and Asia both project are not successful=P(A')*P(B')=0.8*0.5=0.4

P(B'|A')=P(B'∩A')/P(A')=0.4/0.8=0.5

This can be done by another independence property for conditional probability

P(B|A)=P(B)

P(B'|A')=P(B')

P(B'|A')=0.5

b)

Probability of at least one of two  projects will be successful means that the probability of success of Asia project or probability of success of Europe project  or probability of success of Europe and Asian project which is P(AUB).

P(AUB)=P(A)+P(B)-P(A∩B)

P(AUB)=0.2+0.5-0.1

P(AUB)=0.6

c)

Probability of only Asian project is successful given that at least one of the two projects is successful means that probability of success of project Asia while the project Europe is not successful denoted as P((A∩B')/(A∪B))=?

P((A∩B')/(A∪B))=P((A∩B')∩(A∪B))/P(A∪B)

P((A∩B')∩(A∪B))=P(A∩B')*P(A∪B)

P(A∩B')=P(A)*P(B')=0.2*0.5=0.10

P((A∩B')∩(A∪B))=0.1*0.6=0.06

P((A∩B')/(A∪B))=0.06/0.6=0.1

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Mrs. Hinojosa had 75 feet of ribbon. If each of the 18 students in her
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