When dividing 22 into 121 , you are cosidering how many times 22 goes into 121. This is called division.
Now how do we use division to find this?
well we do 22 over 121 or 22/121
The next step is the conversion to decimal.
How do we figure this out? well we use multiplication through the remainder theorem. The way this works is we figure out how many times 121 goes into a quantity of another number so,
121 goes into 22 how many times. Well 0, thus by the reaminder theorem we will add a zero assuming that we put a decimal place so now we know the number is atleast .XX
Now we have 220, so how many times does 121 go into 220? Well 1. We can add that to our number .1XX and we subtract that from 220 and then add a zero.
220-121 is 99 plus add a zero so we now have 990. 121 goes into 990 how many times? 8 times so we know the number is .18
This process could be continued forever, but there is no need. I hope I explained this well. Explaining core concepts like this generally should be done in person with someone.
Using the binomial distribution, it is found that there is a:
a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.
b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.
c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.
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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.
Binomial probability distribution

The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.96516 probability of a chipmunk living through the year, thus

Item a:
- Two is P(X = 2) when n = 2, thus:

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.
Item b:
- Six is P(X = 6) when n = 6, then:

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.
Item c:
- At least one not living is:

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.
A similar problem is given at brainly.com/question/24756209
Answer:
I believe you typed your final answer choice incorrectly, as it should read 960 which is the correct answer
Step-by-step explanation:
the volume is 1920
1920/2=960
Answer:
100%
Step-by-step explanation:

Medians are the line segments that divides a side of Triangle into two equal parts, each having equal length. and since triangles have 3 sides, they have 3 medians as well.