Answer: 6
Step-by-step explanation:
13-7=6
1. 5+4
2. 7+2
The answer is 9.
I hope I helped! :)
If the boat initially cost $11850 and INCREASED in value by 10% per year, we'd calculate the final value like this:
V = $11850(1+0.10)^8
But if the boat is losing value (depreciating) over time, we'd calculate its final value like this:
V = $11850(1-0.10)^8 = $11850(0.90)^8 = $11850(0.4305) = $5101.04 (answer)
Answer:
-2
Step-by-step explanation:
3n+2n+4=9n+12
5n+4=9n+12
5n-9n=-4+12
-4n=8
n=8/-4
n= -2
B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
