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Alekssandra [29.7K]
2 years ago
14

What is the solution set?

Mathematics
1 answer:
Simora [160]2 years ago
3 0

Answer:

5'3

Step-by-step explanation:

trust me I know what im talking about

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Please help ASAP I’m confused<br><br> I WILL GIVE BRAINLIEST
neonofarm [45]

Answer: x=4.7434

Step-by-step explanation:

Use the pythagorean theorem a^{2} +b^{2} =c^{2}

plug in and solve

x^{2} +3x^{2} =(3\sqrt{10}) ^{2}

4x^{2} =90

x^{2} =22.5

x=4.7424

if you need to solve for the sides

3x = 3(4.7434) = 14.2302

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2 years ago
Evaluate the function.<br> f(x) = -x^2 - 4x + 13<br> Find f(3)
julia-pushkina [17]

Answer: i believe the answer is 10

Step-by-step explanation:

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2 years ago
Find the perimeter and area of a triangle with a base of 9 cm, height of 9.3 cm, and sides of 12 cm and 19 cm.
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Answer:multiply i learnt that in mg class

Step-by-step explanation:

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2 years ago
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Wait what’s j I’m confused
5 0
3 years ago
in a game of poker, five players are each dealt 5 cards from a 52-card deck. how many ways are there to deal the cards?
Jlenok [28]

The number of ways to deal 5 cards to 5 players from a 52-card deck in a game of poker is (52!)/[(27!)*(5!)^5].

  • Permutations and combinations define nCr as ways of selecting 'r' number of items from 'n' items. 
  • nCr = (n!)/[r!(n-r)!]
  • here we want to deal 5 playing cards to each player.once we deal 5 playing cards to any participant,
  • the playing cards left inside the deck are reduced through five.
  • We deal a total of 25 playing cards, i.e., 5 playing cards to 5 gamers.
  • The number of ways to deal five playing cards to the primary participant is 52C5.The number of approaches to deal 5 playing cards to the second one participant is 47C5.
  • The wide variety of ways to deal 5 cards to the 0.33 player is 42C5.
  • The variety of methods to deal 5 cards to the fourth participant is 37C5.
  • The quantity of ways to deal 5 playing cards to the 5th player is 32C5.
  • the full quantity of methods is the general multiplication.
  • The total number of solutions = 52C5 * 47C5 * 42C5 * 37C5 * 32C5
  • When we simplify, we get (52!)/[(27!)*(5!)^5]. 

To learn more about permutation, visit :

brainly.com/question/1216161

#SPJ4

3 0
11 months ago
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