Answer:
y = 1/5 x + 8
Step-by-step explanation:
slope of line j: m = -(1/-5) = 1/5
j pass (5,9): (y-9)/(x-5) = 1/5
y-9 = 1/5(x-5) = 1/5 x - 1
y = 1/5 x + 8
72degrees that the agngle its easy
X^2 - 49 = (x + 7)(x - 7) = x^2 - 7x + 7x = 49 = x^2 - 49
The answer is True, trust me on this one
Answer:



And in the figure attached we see the limits with the percentages associated.
Step-by-step explanation:
For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%
We can find the limits and we got:



And in the figure attached we see the limits with the percentages associated.