Answer:
Hi there, $4.04 should be his finance charge.
Step-by-step explanation:
18/3=6
12/2=6
24/4=6
30/5=6
36/6=6
The percent of students that are aged 19 years or more is determined as 84%.
<h3>One standard deviation below the mean</h3>
In a normal distribution curve 1 standard deviation below the mean is defined as follows;
- 1 std below mean : M - d = 16%
M - d = 20.6 yrs - 1.3 yrs = 19.3 years ≈ 19 years
19 years or more will occur at (M - d) + (M) + (M + 2d) = 100% - (M - d)
= 100% - 16%
= 84%
Thus, the percent of students that are aged 19 years or more is determined as 84%.
Learn more about normal distribution here: brainly.com/question/4079902
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answer: where is the question?
Given the equation:

You know that a lab technician finds that a sample of fluid has this pH:

Then, in order to find the hydrogen ion concentration of the fluid, you need to follow these steps:
1. Substitute the pH given in the exercise into the equation:

Multiply both sides by -1:

2. Solve for:

Remember that, by definition:

In this case, you can identify that:

Hence, substituting values and simplifying, you get:

Therefore, the answer is: