Find two Consecutive Integers such that the larger is nine more than twice the smaller
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Answer:
Step-by-step explanation:
The sum is larger than 9, it means we have: 10, 11, and 12
- To get the outcome is 12, we have only one way is that the two dice shows face-6. The probability to have 12 is:
P(12) = =
- To get 11, we have it two ways once dice shows face-5 and the other shows face-6 and vice versa
P(11) = 2* =
- To get 10, we have it three ways ( once dice shows face-5 and the other shows face-6 and vice versa , two dice show 5)
P(10) = 3* =
So the probability of getting a number larger than 9 for the first time on the third roll is:
P(12) + P(11) +P(10 )
= +
+
=