1. 5/11
2. 11
3. 2
These are all just properties of logarithms.
Answer:
28j+21
Step-by-step explanation:
remember to isolate the variable. in this case it would be j. after you do that it should be pretty simple
Answer:
Option c is right.
Step-by-step explanation:
Given is a parabola y =x^2
From that transformation is done to get parabola as
y =(0.2x)^2
We find that instead of x here we use 0.2x
i.e. New x = 5 times old x
Hence there is a horizontal expansion of scale factor 5.
We can check with any point also
When y =4, x=2 in the parent graph
But when y =4 , we have x = 10 in the new graph
i.e. there is a horizontal expansion of scale factor 5.
(1 , -3)
(-3, 4)
Y2-y1/x2-x1
4 - -3 / -3 - 1
-7/ -4
Your slope is -1.75
Hope this helps *smiles*
