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3 years ago

What is word processing?

Computers and Technology

2 answers:

jasenka [17]3 years ago

4 0

I just took the quiz on edg. its D) Creating or changing documents with text in them

butalik [34]3 years ago

3 0

A. Citing sources for documents you found on the web

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Any device that uses light to read and write information.

Ilya [14]

I think Optical Drive does.

8 0

3 years ago

Read 2 more answers

Direct Mapped Cache. Memory is byte addressable. Fill in the missing fields based upon the properties of a direct-mapped cache.

xz_007 [3.2K]

The question given is incomplete and by finding it on internet i found the complete question as follows:

Direct Mapped Cache.

Memory is byte addressable

Fill in the missing fields based upon the properties of a direct-mapped cache. Click on "Select" to access the list of possible answers Main Memory Size Cache Size Block Size Number of Tag Bits 3 1) 16 KiB 128 KiB 256 B 20 2) 32 GiB 32 KiB 1 KiB 3) 64 MiB 512 KiB 1 KiB Select] 4 KiB 4) 16 GiB 10 Select ] Select ] 5) 10 64 MiB [ Select ] 6) Select] 512 KiB 7

For convenience, the table form of the question is attached in the image below.

Answers of blanks:

1. 3 bits

2. 20 bits

3. 64 MB

4. 16 MB

5. 64 KB

6. 64 MB

Explanation:

Following is the solution for question step-by-step:

Part 1:

No. of Tag bits = No. of bits to represent

Tag bits = Main memory - cache size bits -------- (A)

Given:

Main memory = 128 KB = $2^7 * 2^{10} = 2^{17}$

Cache Memory = 16 KB = $2^4 * 2^{10}= 2^{14}$

Putting values in A:

Tag bits = 17 - 14 = 3 bits

Part 2:

Tag bits = Main memory - cache size bits -------- (A)

Given:

Main memory = 32 GB = $2^5 * 2^{30} = 2^{35}$

Cache Memory = 16 KB = $2^5 * 2^{10}= 2^{15}$

Putting values in A:

Tag bits = 35 - 15 = 20 bits

Part 3:

Given:

Tag bits = 7

Cache Memory = 512 KB = $2^9 * 2^{10} = 2^{19}$

So from equation A

7 = Main Memory size - 19

Main Memory = 7 + 19

Main memory = 26

Main Memory = $2^6 * 2^{20} = 64 MB$

Part 4:

Given that:

Main Memory Size = $2^4 * 2^{30} = 2^{34}$

Tag bits = 10

Cache Memory Bits = 34 - 10 = 24

Cache Memory Size = $2^4 * 2^{20} = 16 MB$

Part 5:

Given that:

Main Memory Size = 64 MB = $2^6 * 2^{20}$

Tag bits = 10

Cache Memory Bits = 26 - 10 = 16

Cache Memory Size = $2^{16} = 2^6 * 2^{10} = 64 KB$

Part 6:

Cache Memory = 512 KB = $2^9 * 2^{10} = 2^{19}$

Tag Bits = 7

Main Memory Bits = 19 + 7 = 26

Main Memory size = $2^{26} = 2^6 * 2^20 = 64 MB$

i hope it will help you!

6 0

3 years ago

Suppose that a program asks a user to enter multiple integers, either positive or negative, to do some calculation. The data ent

KatRina [158]

Answer:

d) An alphabetic character

7 0

3 years ago

: how can you reduce file size so that files can be sent more efficiently across the internet

Rina8888 [55]

You can compress them. ZIP is the most well known protocol.

8 0

3 years ago

How do most database users perform data searches?

defon

Answer:

by using forms

Explanation:

Most of the database users perform the data searches by using the forms. A form can be used to enter, edit and display the data from the data source. Its a user interface in fact that fetches the data from the database. Reports have used the display the data for a certain type of user, and the viewing table does not look feasible to search from a very large database, and the databases are usually large. No calculation is required for searching the data, and we only need to write queries in the right syntax. Hence, here the correct option is by using forms.

7 0

3 years ago