Answer:
351°
Step-by-step explanation:
-369° + 360° = -9°. This is in Quadrant IV. If you want a reference angle in Quadrant I, find the positive angle between 0 and 360° that has the same terminal point at does -9°. It is 360° - 9° = 351°
Answer:
Step-by-step explanation:
![5\sqrt[3]{x+8}=35\\ \\ \sqrt[3]{x+8}=7\\ \\ x+8=7^3\\ \\ x+8=343](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7Bx%2B8%7D%3D35%5C%5C%20%5C%5C%20%5Csqrt%5B3%5D%7Bx%2B8%7D%3D7%5C%5C%20%5C%5C%20x%2B8%3D7%5E3%5C%5C%20%5C%5C%20x%2B8%3D343)
ΔBAC ≅ ΔDAC by ASA congruency
Step-by-step explanation:
Congruency of any triangle can be proved by either of these four criteria. These include
SSS, SAS, ASA, AAS where S= sides and A= Angles
In the given figure ΔBAC & ΔDAC
Since the line, AC is a common angular bisector of ∠BAC and ∠DAC
∴ ∠BAC = ∠DAC ∵ AC is an angular bisector and bisects the ∠BAD into two halves
∠BCA=∠DCA ∵AC is an angular bisector and bisects the ∠DCB into two halves
AC=AC ∵Common side
∴ ΔBAC ≅ ΔDAC ⇒by Angle-Side-Angle (ASA) congruency criterion
