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Eduardwww [97]
4 years ago
8

X²-x-12=0 Describe the number and types of roots using the discriminant Show steps please

Mathematics
1 answer:
pickupchik [31]4 years ago
8 0

Answer:

2 real roots

Step-by-step explanation:

The discriminant is b^2 -4ac  where ax^2 +bx -c

If b^2 -4ac > 0 we have 2 real roots

b^2 -4ac = 0 we have 1 real root

b^2 -4ac < 0 we have 2 complex roots

x²-x-12=0

a =1 b=-1  c = -12

(-1)^2 - 4(1)*(-12)

1 +48

49 > 0

2 real roots

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