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Vikentia [17]
3 years ago
5

Find the length of segment GH.

Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

it's 21-12 which is equal to 9

saw5 [17]3 years ago
7 0
Full length minus length f- g
21-12=9
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NO LINKS <br> Please help
Triss [41]

Answer:

V≈1287.88

A≈1152.98

Step-by-step explanation:

7 0
2 years ago
What is the equvilent fraction of 7•4 OVER 1002•9
galina1969 [7]
14 over 4509 would be an equvilent fraction
7 0
3 years ago
Read 2 more answers
Help I'm not sure if this is the answer?<br><br> (This question is about trigonometric ratios)
dem82 [27]

9514 1404 393

Answer:

  (b) 15.32

Step-by-step explanation:

You can use your triangle sense to answer this.

The side x will always be shorter than the hypotenuse, 20. This eliminates the last two choices.

If the angle is 45°, then the sides are equal at about 0.707 times the length of the hypotenuse. That would make them 0.707×20 = 14.14. Since the angle is greater than 45°, the opposite side will be greater than 14.14. Only one answer choice fits between 14 and 20: the second choice -- 15.32.

__

The mnemonic SOH CAH TOA reminds you of the relation ...

  Sin = Opposite/Hypotenuse

  sin(50°) = x/20

  x = 20×sin(50°) . . . . multiply by 20 to find x

  x ≈ 15.32 . . . . . . . . . use your calculator to evaluate

__

The attachment is intended to show how the triangle side lengths change with angle.

3 0
3 years ago
Jack wrote this expression to describe how much he will pay for flowers.
kap26 [50]
C

5 x f

5 = price for flowers
f = variable = how many flowers.
3 0
3 years ago
Read 2 more answers
9. Stan’s Deli is situated inside a large industrial park. The weekday gross sales at Stan’s average $1,240, with a standard dev
mr Goodwill [35]

Answer:

0.9792

Step-by-step explanation:

Data provided in the question:

Average gross sales = $1,240

Standard deviation = $180

sample size = 40

Now,

standard deviation of sample average

= \frac{\textup{Standard deviation}}{\sqrt{n}}

= \frac{180}{\sqrt{40}}

= 28.46

Now,

z value for 1200 = \frac{(1200-1240)}{28.46} = -1.4,

and,

p value for (z = -1.4) = 0.0808

therefore,

P(average < $1200) = 0.0808

Thus,

probability that the average over the next 40 weekdays will exceed $1,200

= 1 - 0.808

= 0.9792

7 0
3 years ago
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