Let's find out the gradient (Slope " m ") of line q ;
Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :
Now, plug in the value of gradient ~
here we can clearly observe that, the Area under the curve can easily be represented as :
Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Answer:
2n + 11
Step-by-step explanation:
You can combine 4n and -2n.
You get 2n + 11
There are two equation:
1) From Kim
2) From Daniel
Let:
x be the cost of rolls of plain wrapping paper
y be the cost of rolls of shiny wrapping paper
Kim:
7x + 8y = 140
Daniel:
14x + 7y = 154
<u>Using elimination method:</u>
(7x + 8y = 140) * -2 (Multiplying the equation by -2)
-14x - 16y = -280
-14x -16y = -280
14x + 7y = 154
------------------------------
0x - 9y = -126
9y = 126 (Negative sign cancels from both sides)
y = 126 /9
y = 14
The cost of each shiny wrapping paper is $14.
Now solve x, you pick any two equation to solve for x.
7x + 8y = 140
7x + 8(14) = 140 (You know from above y =14)
7x + 112 = 140
7x = 28
x = 28/7
x = 4
The cost of each plain wrapping paper is $4.
Solution: (4,14)
