Question

How to figure out answer ?

Answer 1

$\sin 45=\dfrac{y}{11\sqrt6}\\ \dfrac{\sqrt2}{2}=\dfrac{y}{11\sqrt6}\\ 2y=11\sqrt{12}\\ y=\dfrac{11\sqrt{12}}{2}\\\\ \tan 60=\dfrac{x}{y}\\ \tan 60=\dfrac{x}{\dfrac{11\sqrt{12}}{2}}\\ \sqrt3=\dfrac{2x}{11\sqrt{12}}\\ 2x=11\sqrt{36}\\ 2x=66\\ x=33 \Rightarrow D$