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Airida [17]
2 years ago
12

Verify that the divergence theorem is true for the vector field f on the region

Mathematics
1 answer:
timofeeve [1]2 years ago
5 0
\mathbf f(x,y,z)=3x\,\mathbf i+xy\,\mathbf j+4xz\,\mathbf k
\implies\nabla\cdot\mathbf f(x,y,z)=3+x+4x=3+5x

\displaystyle\iint_{\partial E}\mathbf f(x,y,z)\,\mathrm dS=\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV
=\displaystyle\int_{z=0}^{z=3}\int_{y=0}^{y=3}\int_{x=0}^{x=3}(3+5x)\,\mathrm dx\,\mathrm dy\,\mathrm dz
=\displaystyle9\int_0^3(3+5x)\,\mathrm dx
=\dfrac{567}2
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one-third of a number x is equal to 22 less than the number. Write and solve an equation to find the number.
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1  \div 3x = 22 - x
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2 years ago
1. Simplify. 5–1(3–2)
konstantin123 [22]

Answer with explanation:

Using following law of indices

1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}

1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}

9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9

8. A number raised to a negative exponent is negative.

Explaining with the help of few examples

 1.2^{-3}=\frac{1}{2^3}=\frac{1}{8}\\\\ 2.(-3)^{-3}=\frac{1}{(-3)^{3}}=\frac{-1}{27}

Option C: Sometimes

1.Option B

2.Option A

3.Option C

4.Option A

5.Option D

6.  81 \times 10^6

7.Option B

8.Option C

9.Option A

10.Option  1.28 r^2 \times t^9

4 0
3 years ago
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2 years ago
I really need help with this i beg you !!
sweet-ann [11.9K]

Answer:

The perimeter and area of the square are 56 units and 196 square units, respectively.

Step-by-step explanation:

The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is \sqrt{2} time the length of any of its legs. If the hypotenuse has a measure of 7\sqrt{2}, then the legs of the triangle have a measure of 7.

Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.

Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:

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Where l is the side length of the square.

If we know that l = 14, then the perimeter and area of the square are, respectively:

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The perimeter and area of the square are 56 units and 196 square units, respectively.

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