Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a)
, such that f(x)= -xf'(x).(5marks) (%4h) 4
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Answer:
Perimeter of a square that measure 5.35 on one side is, 21.4 cm
Step-by-step explanation:
Perimeter of a square is the total length of the boundary of a square.
It is given by:
......[1] where
P represents the perimeter of square,
a represents the side of square.
Given: a = 5.35 cm
Substitute this value in [1] we get;
P = 4(5.35) = 21.4 cm
therefore, the perimeter of a square is, 21.4 cm