Answer:
x ≈ 63.27
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan49° = =
=
( multiply both sides by 55 )
55 × tan49° = x , then
x ≈ 63.27 ( to the nearest hundredth )
Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a)
, such that f(x)= -xf'(x).(5marks) (%4h) 4
1 answer:
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