The amount invested at 11% is $5,000
The amount invested in stock is $14,000
What is the net profit on both investments?
The profit of each investment is the rate of return or loss multiplied by the amount invested
Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%
net profit=(11%*x)+(19000-x)*-3%
net profit=130
130=(11%*x)+(19000-x)*-3%
130=0.11x-570+0.03x
130=0.14x-570
130+570=0.14x
700=0.14x
x=700/0.14
x=$5,000
Amount invested in stock=19000-x
Amount invested in stocks=19000-5000
Amount invested in stocks=$14,000
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Step-by-step explanation:
i assume this is the question you asked me to look at.
Well, angle 116° and y are supplementary angles
therefore,116°+y=180°
y=180°-116°=64°
Now to find x
x+y+125+72=360°
x+64+125+72=360
x+261=360
x=360-261=99°
Answer:
given n(A) = 14
n(B) = 15
n(A∩B ) = 15
Step-by-step explanation:
now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)
n(AUB) = 14+15-6 = 23.Answer
To solve this, you need to make the amount they built on Monday and the amount they built on Tuesday compatible with each other so you can add them together to subtract that amount from 4.
Start by multiplying 1/2 by 3, and 1/3 by 2.
This gives you 3/6 and 2/6. Now add them together:
3/6 + 2/6 = 5/6
Finally, subtract this amount from 4:
4 - 5/6 = 3 1/6 (19/6 works too)
Hope this helps! :)
Answer:
-86
Step-by-step explanation:
5+5=10
10-6=4
4-100=-86
