let's recall that i⁴ = 1.
![\bf i^{85}\implies i^{84+1}\implies i^{(4\cdot 21)+1}\implies i^{4\cdot 21}\cdot i^1\implies (i^4)^{21}\cdot i\implies (1)^{21}\cdot i\implies i](https://tex.z-dn.net/?f=%5Cbf%20i%5E%7B85%7D%5Cimplies%20i%5E%7B84%2B1%7D%5Cimplies%20i%5E%7B%284%5Ccdot%2021%29%2B1%7D%5Cimplies%20i%5E%7B4%5Ccdot%2021%7D%5Ccdot%20i%5E1%5Cimplies%20%28i%5E4%29%5E%7B21%7D%5Ccdot%20i%5Cimplies%20%281%29%5E%7B21%7D%5Ccdot%20i%5Cimplies%20i)
Answer:
option B
(−1, 0) and (0, 6)
Step-by-step explanation:
Given in the question two equations,
Equation 1
y =−x² + 5x + 6
Equation 2
−6x + y = 6
plug value of y in second equation
−6x −x² + 5x + 6 = 6
-x² -6x + 5x +6 - 6 = 0
-x² - x + 0 = 0
-x² -x = 0
-x(x+1) = 0
x = 0
and
x = -1
plug value of x in second equation to find y
x = 0
−6(0) + y = 6
0 + y = 6
y = 6
and
x = -1
−6(-1) + y = 6
6 + y = 6
y = 0
Answer:
596.032
Step-by-step explanation:
The answer is typed wrong.
Using a calculator: 6.4 x 6.7 x 13.9 = 596.032
Tell your teacher that answer is not there. It's typed wrong.
Hoped this helped! :)