Answer:
I'm guessing it's C because it's the only one that looks right
Answer: Third Option

Step-by-step explanation:
We have the following exponential equation

We must solve the equation for the variable x
To clear the variable x apply the
function on both sides of the equation

Simplifying we get the following:

To simplify the expression
we apply the base change property

This means that:

Then:



First problem:
cos (theta)=1
Using the inverse cosine function, you get theta = 0.
Now we find tan 0 = 0
cot(theta) = 1/tan(theta) = 1/0
Division by zero is undefined, so the answer is d. undefined
Second problem:
cos (theta)=1
Use the inverse cosine function.
theta = 0°
Answer: c. 0°
20/2-10/5. You divide 20 by 2 and subtract that from 10 divided by 5