Ask question

Ask question

All categories

lisabon 2012 [21]

3 years ago

6

A menu offers a choice of 22 salads, 77 main dishes, and 55 desserts. How many different meals consisting of one salad, one m

ain dish, and one dessert are possible?

1 answer:

weqwewe [10]3 years ago

8 0

Answer:

70 different meals

Step-by-step explanation:

A menu offers a choice of 2 salads, 7 main dishes, and 5 desserts

There are 3 types of choices are given

each one have different choices. we need to select one salad, one main dish and one dessert

To find the number of different meals we multiply the different choices

$2 \cdot 7 \cdot 5=70$

so 70 different meals

You might be interested in

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

Five years ago, John's age was half of the age he will be in 8 years. How old is he now?

notka56 [123]

J-5=0.5J+8
J=0.5J+13
0.5J=13
J=26

8 0

2 years ago

Read 2 more answers

What are the coordinates of point A?<br><br> A. (5,4)<br> B. (4,5)<br> C. (4,6)<br> D. (6,4)

erica [24]

The answer is A . (5,4)

3 0

2 years ago

Read 2 more answers

5x + 2y = 1<br> x - 2y = 5<br><br> Solve by substitution <br><br> Thank you

quester [9]

Answer:

The answer is ( 1 , -2) in point form or x = 1 , y = -2 in eqaution form.

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

7 0

3 years ago

2+2= what plz I need help

jekas [21]

Answer:4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers