Answer:
(3x + 5)/2 = 7
Step-by-step explanation:
If you substitute 3 for x, you get the equation:
(3(3) + 5)/2 = 7
(9 + 5)/2 = 7
14/2 = 7
Answer:
368<939`01^9292^91 ibtimes
First find the length of leg BC by using the Pythagorean theorem BC=132+52=12 ft if we find the midpoint of BC which is 6 ft we find where the angle bisector would touch the BC. From there we construct another triangle ANC where AC is equal to 5 ft and NC is equal to 6 ft where we can again use the Pythagorean theorem to find the length of the hypotenuse which is the angle bisector AN=Angle Bisector=62+52<span>=7.8102 ft.</span>
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Questions:
(a) What is a simplified expression for (x + y) – (x – y)?
(b) Carlotta thinks that
is the same as
. Which statement shows that it is NOT the same?
Answer:


Step-by-step explanation:
Solving (a):
Given

Required
Simplify

Open brackets

Collect Like Terms



Solving (b):
Given
and 
Required
Which expression shows they are not the same
The expression that shows this is:

Take for instance; y=2
Substitute 2 for y in 

Evaluate all exponents



The above expression supports 
It is the best option, 6 Teaspoons.