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SOVA2 [1]
4 years ago
7

2 x + 5 = 27 solve for x

Mathematics
2 answers:
Mnenie [13.5K]4 years ago
8 0

Answer:

x=11

Step-by-step explanation:

2x+5=27

Subtract 5 on both side of 27

You will get 2x=22

Then divide it by 2

You will get x=11

ANTONII [103]4 years ago
4 0

Answer:

x=11 is the solution of the equation.

Step-by-step explanation:

SIMPLE EQUATIONS:-

2x+5=27. (By Transpotion Method)

2x=27-5. (Transposing 5 from LHS to RHS). (addition changes to subtraction)

2x=22. (Transposing 2 from LHS to RHS).

(multiplication changes to division)

x=22÷2.

x=11

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Can someone please help me with this geometry homework?
Leno4ka [110]

The distances between the two points, in units, are given as follows:

7. \sqrt{2}

8. 2\sqrt{17}

9. 3\sqrt{2}

10. 3\sqrt{5}

The midpoints are given as follows:

11. (7,-4.5).

12. (2,4).

13. (7,0.5).

14. (5.5,-1.5).

<h3>What is the distance between two points?</h3>

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For item 7, the points are (-3,-2) and (-4,-3), hence the distance is:

D = \sqrt{(-4 + 3)^2 + (-3 + 2)^2} = \sqrt{2}

For item 8, the points are (-3,1) and (5,3), hence the distance is:

D = \sqrt{(5 + 3)^2 + (3 - 1)^2} = \sqrt{68} = 2\sqrt{17}

For item 9, the points are (-3,0) and (0,-3), hence the distance is:

D = \sqrt{(0 + 3)^2 + (-3 - 0)^2} = \sqrt{18} = 3\sqrt{2}

For item 10, the points are (1,-2) and (4,4), hence the distance is:

D = \sqrt{(4 - 1)^2 + (4 + 2)^2} = \sqrt{45} = 3\sqrt{5}

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence, for item 11, the midpoint is given by:

[0.5(9 + 5), 0.5(1-10)] = (7,-4.5).

For item 12, the midpoint is given by:

[0.5(-5 + 9), 0.5(7 + 1)] = (2,4).

For item 13, the midpoint is given by:

[0.5(9 + 5), 0.5(9 - 8)] = (7,0.5).

For item 14, the midpoint is given by:

[0.5(10 + 1), 0.5(4 - 7)] = (5.5,-1.5).

More can be learned about the distance between two points at brainly.com/question/18345417

#SPJ1

8 0
2 years ago
Which function has the greatest starting value?. . A.. xy. 1−3. 2−8. 3−13. . . B.. y = 3x – 8. . C.. 8x + 4y = 16. . D.. A linea
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The problem ask to choose among the following functions in the given choices that has the greatest value and the best answer among the following function is letter D. a linear function that goes through point 2,0 and point 0,2. I hope you are satisfied with my answer 
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4 years ago
Write the equation of a sine function that has the following characteristics.
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Answer:

\displaystyle y = 7\sin(9\pi(x +   {1}/{4}) )

Step-by-step explanation:

we are given

  • Amplitude:7
  • Period:9π
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remember that,

\displaystyle y = A \sin(B(x + C) )+ D

where A is the Amplitude

B is the Period

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note that, since D isn't given we'll take it 0

altogether substitute:

\displaystyle y = 7\sin(9\pi(x +   {}^{1}/_{4}) )+ 0

hence,

our equation is

\displaystyle y = 7\sin(9\pi(x +   {}^{1}/_{4}) )

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irakobra [83]
The answer is x=2/3!! Hope this helped
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3 years ago
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Which values of a and b make the following equation true? (5x7y2)(-4x4y5)=-20xayb
Kaylis [27]

Answer:

The values of a and b are a = 11 , b = 7

Step-by-step explanation:

* Lets explain how to solve the problem

* In the exponential functions we have some rules

1-  In multiplication if they have same base we add  the power

# Ex: b^m  ×  b^n  =  b^(m + n) ⇒ b is the base , m and n are the powers

2- In division if they have same base we subtract  the power

# Ex: b^m  ÷  b^n =  b^(m – n) ⇒ b is the base , m and n are the powers

3- If we have power over power we multiply them

# Ex: (b^m)^n = b^(mn) ⇒ b is the base , m and n are the powers

* Lets solve the problem

∵ The equation is (5x^{7}y^{2})(-4x^{4}y^{5})=-20x^{a}y^{2} ⇒ (1)

- At first multiply the coefficients

∵ -4 × 5 = -20

- Multiply the base x

∵ (x^{7})(x^{4})=x^{7+4}=x^{11}

- Multiply the base y

∵ (y^{2})(y^{5})=y^{2+5}=y^{7}

∴ (5x^{7}y^{2})(-4x^{4}y^{5})=-20x^{11}y^{7} ⇒ (2)

- By comparing (1) and (2)

∴ a = 11 and b = 7

* The values of a and b are a = 11 , b = 7

5 0
3 years ago
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