All categories

3 years ago

6/3 + (-1/6) = ? (These are supposed to be fractions)

Mathematics

1 answer:

Phoenix [80]3 years ago

6 0

Answer: 11/6 or 1 5/6

Simplify 6/3

6/3÷3/3=2/1

Change 2/1

2/1×6/6=12/6

New Problem: 12/6+(-1/6)

Add

12+-1/6=11/6

Simplify

11/6 = 1 5/6

You might be interested in

MATH HELP PLEASE

miv72 [106K]

2/16=1/8 = 0.125 12.5%

4 0

3 years ago

Read 2 more answers

A cylindrical glass of soda has a mass of 700g. The glass itself has a mass of 80g. If the glass has a radius of 4cm and a heigh

rusak2 [61]

Answer:

GATORADE

Step-by-step explanation:

7 0

3 years ago

Write an equation in slope-intercept form (0,2) (7,-1)

maksim [4K]

Answer:

y=-3/7x+2

Step-by-step explanation:

first formula (Slope): y2-y1/x2-x1

-1-2/7-0= -3/7

second formula (point slope): y-y1=m(x-x1)

y-2=-3/7(x-0)

(distribute the -3/7)

y-2=-3/7x-0

(add 2 to both sides)

y=-3/7x+2

6 0

3 years ago

Nathan has three pieces of wood the first is 9.8 feet in length the second is 7.5 feet in length and the third is 12 feet in len

MA_775_DIABLO [31]

Answer:

17.7

Step-by-step explanation:

5 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

1 year ago