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Scorpion4ik [409]
4 years ago
14

0.032 divided 4 = ___

Mathematics
1 answer:
Zigmanuir [339]4 years ago
8 0
<span>0.008. Hope this helps in any way.</span>
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I need help fast!!!!!!!!!!!
Vedmedyk [2.9K]

Answer:

Track 2

Step-by-step explanation:

180 degrees would turn the train completely around so if it entered on track 2 then it left on track 2

7 0
3 years ago
Each model represents one whole. In which model does the shaded section represent the product of 5/8 and 3/8?
Mnenie [13.5K]
We can’t answer this question without a photo of the model. Can you post a photo of the question?
8 0
4 years ago
Explain how to estimate the quotient using compatible<br>numbers.plz help fast ​
Nadya [2.5K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To estimate the quotient, make the fractions "like" fractions. To do this, you need to make the fractions have the same denominator, and turn them into improper fractions.

Step-by-step explanation:

27\frac{2}{3} = 27 \frac{20}{30}

3\frac{9}{10} = 3\frac{27}{30}

Now the denominators are the same --> they are "like" fractions.

27\frac{20}{30} + 3\frac{27}{30} = ?

27\frac{20}{30} + 3\frac{27}{30} = (27 + 3) + (\frac{20}{30} + \frac{27}{30})

27\frac{20}{30} + 3\frac{27}{30} = (30) + (\frac{47}{30})

27\frac{20}{30} + 3\frac{27}{30} = (30) + (1 \frac{17}{30})

27\frac{20}{30} + 3\frac{27}{30} = 31 \frac{17}{30}

Your answer is 31\frac{17}{30}.

I hope this helps!

3 0
4 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
Please someone help me (NO LINKS) (NO LYING)
romanna [79]
Number one 42 cubes .
6 0
3 years ago
Read 2 more answers
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