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Gemiola [76]
3 years ago
15

What is 9/8 x 1/9 equals what fraction?

Mathematics
1 answer:
Alborosie3 years ago
4 0
\frac{9}{8} * \frac{1}{9}
On multiplying;
\frac{9}{72}
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What percent of 99 is 90?
Yuri [45]

Answer:

91%

Step-by-step explanation:

We can use the formula \frac{is}{of}=\frac{percent}{100}

  • "is" is 90
  • "of" is 99
  • "percent" is what we are solving for so we will denote it as x

Substituting in our values we get \frac{90}{99}=\frac{x}{100}

  • We will need to cross multiply here to get (90)(100) = (x%)(99)
  • This simplifies to 9000 = 99x%
  • Dividing by 99 on both sides we get 90.9% → x = 91%
4 0
2 years ago
What is the slope of the line 3х + 5у — 2х + Зу
Shkiper50 [21]

Answer:

-1/8

Step-by-step explanation:

8 0
3 years ago
Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )
Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0
2 years ago
Read 2 more answers
Solve each equation.<br> 1/3a = -5 a = ?<br> 12 - b = 12.5 b = ? <br> -0.1 = -10c c = ?
Rina8888 [55]

Answer:

a = -15, b = -.5, c = -1

Step-by-step explanation:

1/3a = -5 --> multiply each side with 3 --> a = -15

12 - b = 12.5 --> subtract 12 from both sides --> -b = .5 --> multiply each side with -1 to get b positive --> b = -.5

.1 = -10c --> multiply each side with -10 --> c = -1

8 0
2 years ago
If 29% of the students wore jeans what percent of he students did not wear jeans?
igor_vitrenko [27]

So you just take 100% - 29% = 71%

So 71% of the students did not wear jeans


7 0
2 years ago
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