Answer:
The second integer is greater than the first.
Step-by-step explanation:
Since the <u>first</u> integer is the leftmost out of the two, this means that the second one must be greater than the first since it is to the right of it.
Here, we need to check for all pairs by substituting the value of x & y,
1) 11 + 11 = -14(-2-2)
sides are not equal.
2) -11 + 11 = -14(2 - 2)
0 = 0
sides are equal.
In Short, Your Answer would be Option 2
Hope this helps!
Answer:
C
Step-by-step explanation:
Y^3+5y^2-14y
y(y^2+5y-14)
y(y^2+7y-2y-14)
y(y(y+7)-2(y+7))
y(y-2)(y+7)
So there are infinite solutions with the only restriction being that y>2 as V>0
Answer:
y+6=-3y+26
Step-by-step explanation:
y+3y=26-6
4y=20
y=20/4
y=5