In this case, we have a colored dot at -1 and a white dot at 3, then the interval notation for that graphed interval will be:
[-1, 3).
<h3>How to write the interval of values in the graph using interval notation?</h3>
First, remember that the symbols ( and ) are used for ends that do not belong to the interval.
For example, if our interval is 1 < x < 2
1 and 2 do not belong to the solution interval, thus, the solution interval is (1, 2).
While [ and ] are used when the ends belong. For example, in:
1 ≤ x ≤ 2
The interval notation is [1, 2]
And in:
1 < x ≤ 2
(1, 2]
And so on.
On the number line, the notation is:
- Colored dot: the point belongs to the interval.
- White dot: the point does not belong to the interval.
In this case, we have a colored dot at -1 and a white dot at 3, then the interval notation for that graphed interval will be:
[-1, 3).
If you want to learn more about interval notation.
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East common multiple is the smallest multiple both numbers can go into. (Example: the LCM of 10 and 4 is 20, because both 10 and 4 go into 20 and 20 is the smallest number both 10 and 4 can go into. You could just multiply them both, but you'd get 40 and since its a bigger number it would be harder to work with.)
<span>Least common denominator is just the least common multiple as a denominator. (Example: if you wanted to find the LCD of 5/7 and 1/10, you'd have to find the LCM of the demoniators (7 and 10) and then just use that as the denominator when adding fractions with unlikely denominators.) Sorry for such a long answer :P</span>
Answer:
<em>Is a tangent</em>
Step-by-step explanation:
<em>* Great question by the way *</em>
~ By definition, a tangent to circle is a straight line, presently perpendicular to a radius if one. In this case tangent AB should be perpendicular to the radius. If we were to call the center O, we would say AB should be perpendicular to OA. ~
1. Now let us say at the moment that AB is a tangent. If that is so, it should be that m∠A = 90 degrees ( ° ), provided AB is ⊥ to OA by definition.
2. Now the triangle ABO is a right triangle, and with that is should be that Pythagorean Theorem is applied. This can help us prove if AB is a tangent or not. If Pythagorean Theorem is not applicable it would mean ABO is not a right angle triangle, that AB is not ⊥ to OA, and thus can't be a tangent.
3. Let us say x ⇒ side OA, and that side BO = 9 + 8 + 17:
AB^2 + OA^2 = BO^2,
15^2 + x^2 = 17^2,
<em>x = 8</em>
4. Now there are two radii present, OA is only one of them. As radii are ≅, OA = other radii, 8 = 8
5. This proves that Pythagorean Theorem is applicable, that ABO is a right triangle, that m∠A = 90°, and that by definition <em>AB is a tangent</em>
Answer:
201.06
Step-by-step explanation:
Point form: (6,-3)
equation form: x=6, y=-3
