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astraxan [27]
3 years ago
5

Is 11/20 repeating or terminating

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0
It is terminating it is 45/100
wel3 years ago
6 0

11/20 is equal to 0.55

so,...

11/20 is terminating

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alina1380 [7]

Answer:

17:3

Step-by-step explanation:

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Need all of them for Transformation Quadratics
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uduusidir93irisufffdhhdjdf

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Solve 7n + 4 < 9n – 3.
soldier1979 [14.2K]
I hope this helps you

6 0
3 years ago
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0
3 years ago
Simplify 8(xy + 8) + 1. 8xy + 9 8xy + 65 8xy + 73
Advocard [28]

Answer:

8xy + 65

Step-by-step explanation:

8(xy + 8) + 1.

8      x 8=

        64 + 1=

                    65    (8xy + 65)

---------------------------------------------

LINE THE NUMBERS UP AND IT WILL MAKE SENSE

5 0
3 years ago
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