First, combine like terms.
12y+6=6y+12 turns into
12y-6y=12-6, which is
6y=6. Now divide both sides by 6.
y=1
now do a quick check (cause that's always a good idea).
12(1)+6=6(1)+12
12+6=6+12
18=18 ; )
Answer:
4 can be divided by 1 and 2
6 can be divided by 1 and 2
12 is wrong because it can be divided by 1,2, and 4 so it has 6 factors instead of 4
Step-by-step explanation:
Answer:
For w = 18 units perimeter is minimum
P = 2(18 + w)
Step-by-step explanation:
Given;
Area of the rectangle = 324 units²
P is the perimeter
w is the width
Let L be the length of the rectangle
therefore,
P = 2(L + w) ............(1)
also,
Lw = 324
or
L =
..........(2)
substituting 2 in 1
P = 
now,
for minimizing the perimeter
= 0
or
= 0
or
= 0
or
= -1
or
w² = 324
or
w = 18 units
For w = 18 units perimeter is minimum
therefore,
from 2
L = 
or
L = 18 units
objective function for P is:
P = 2(18 + w)
B in has the intersection with quadrant 1 and 3