Example:

This suggests two solutions,

and

.
However, upon plugging these solutions back into the equation, you get

which checks out, but

does not because

is defined only for

(assuming you're looking for real solutions only). So, we call

an extraneous solution, and the complete solution set (over the real numbers) is

.
Weird. I think you just need to look if the point falls on the shaded area. But only (-5,5) does ...
Answer:
23456789
Step-by-step explanation:
Answer:
The Transcontinental Railroad
Step-by-step explanation:
Hope it helps you :)
It is quadratic since a quadratic function is of the form :y=ax²+bx+c ,a,b,c are constants.