Question

Z varies directly with X squared and inversely with Y. When X equals two and Y equals four, Z equals three. What is the value of Z when X equals four and Y equals nine
A: 2/3

B: 16/3

C: 8/3

D: 24

Answer 1

Answer:

B

Step-by-step explanation:

Set up the equation

z = $\frac{kx^2}{y}$

Plug in the numbers to find the value of k

3 = $\frac{k(2^2)}{4}$

12 = 4k

3 = k

Solve to find the value of z

z = $\frac{3(4^2)}{9}$

z = $\frac{3(16)}{9}$

z = 48/9

z = 16/3