Compute the function table Draw the graph of each function f(x) = 2x+1
1 answer:
Answer:
<u>Function Table</u>
<u>x | f(x)</u>
0 | 1
1 | 3
2 | 5
View Image For Graph
Step-by-step explanation:
This function follows the general equation for the slope-intercept formula:
y = mx + b
m is the slope, which is how much the graph move up whenever to move to the right by 1. In our case, our slope is m=2, so every time we move right by 1, we have to move up by 2.
b is the y-intercept. it's basically the starting point when x is 0. In our case, b=1 so we start at (0, 1)
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Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.