A candy distributor needs to mix 10% a fat content chocolate with 40% fat content chocolate to create 200 kg of a 16% fat conten
t chocolate how many kilograms of each kind of chocolate must they use
1 answer:
I like to use an X diagram to solve problems like this. The constituent percentages are on the left, the desired mix is in the middle and the numbers on the diagonals are the difference between the mix and the constituent.
The numbers 6 and 24 here represent the ratio of 40% to 10% chocolate. That 6:24 ratio can be reduced to 1:4. The sum of those ratio units is 1+4 = 5, so each must represent (200 kg)/5 = 40 kg of chocolate.
The mix must consist of
40 kg of 40% fat chocolate
160 kg of 10% fat chocolate
The numbers 6 and 24 here represent the ratio of 40% to 10% chocolate. That 6:24 ratio can be reduced to 1:4. The sum of those ratio units is 1+4 = 5, so each must represent (200 kg)/5 = 40 kg of chocolate.
The mix must consist of
40 kg of 40% fat chocolate
160 kg of 10% fat chocolate
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Answer:
Base of triangle = 2.4 Feet and Height of triangle = 10 feet.
Step-by-step explanation:
This problem can be solved by using formula to calculate area of triangle.
<u>Area of triangle = 1/2*(base*height)</u>
given
Let base of triangle B
height if triangle H
according to problem
The height of a triangle is 2 less than 5 times its base
mathematically it can be expressed as
H = 5*B - 2
Given area of triangle= 12 sq feet
Area of triangle = 1/2*(base*height)
=> 12 = 1/2* {B*(5*B-2)}
=> 24 = 5B^2 - 2B
which is a quadratic equation
It can be solved as given below
Since for side of triangle B cannot be negative number hence B= 12/5 = 2.4
Therefore height of triangle = 5*B - 2 = 5*2.4 - 2 = 12 - 2 = 10
Base of triangle = 2.4 Feet and Height of triangle = 10 feet.
Equation which models this situation is