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charle [14.2K]
3 years ago
14

A candy distributor needs to mix 10% a fat content chocolate with 40% fat content chocolate to create 200 kg of a 16% fat conten

t chocolate how many kilograms of each kind of chocolate must they use

Mathematics
1 answer:
Luden [163]3 years ago
6 0
I like to use an X diagram to solve problems like this. The constituent percentages are on the left, the desired mix is in the middle and the numbers on the diagonals are the difference between the mix and the constituent.

The numbers 6 and 24 here represent the ratio of 40% to 10% chocolate. That 6:24 ratio can be reduced to 1:4. The sum of those ratio units is 1+4 = 5, so each must represent (200 kg)/5 = 40 kg of chocolate.

The mix must consist of
   40 kg of 40% fat chocolate
   160 kg of 10% fat chocolate

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10. Mr. Guerrero left his house and drove north at an average speed of 40 mph.Two hours later, his daughter Miranda left the hou
Charra [1.4K]
Speed=distance / time  ⇒ distance=time x speed
distance=d
time=t
speed= s

d=s*t

Distance  traveled by Mr Guerrero, when his daugther left the house
Data:
s=40 miles/ hour
t=2 hours
d=40 miles/ hour * 2 hours=  80 miles

Total distance traveled by Mr Guerrero:
d=80 miles + 40 miles/hourt    ⇒d=80+40t      (1)

d=total distance.
s=speed.
t=time spent by Miranda for she overtook her father.

Distance traveled by Miranda.
data:

s=48 miles/ hour
d=total distance.
t=time spent by Miranda for she overtook her father.

d=48 miles/hour * t      ⇒d=48t       (2)

With the equations (1) and (2), we make an system of equations:

d=80+40t
d=48t

We can solve this system of equation by equalization method.

80+40t=48t
80=48t-40t
80=8t
t=80/8=10

d=48t
d=48*10=480

Answer: the thistance will be 480 miles.
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3 years ago
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I think the answer is B.
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Step-by-step explanation:

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Answer:

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