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maks197457 [2]
3 years ago
12

What is 5.8 × 106 mg/s in grams per minute?

Mathematics
1 answer:
sasho [114]3 years ago
6 0
The answer is a. 9.7×109g/min
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10y less than or equal to 12x
sattari [20]

10y less than or equal to 12x

10y <= 12x

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Find x. A. 21√2 B. 7 C. 21√3 over 2 D. 21√2 over 2
kkurt [141]

Answer:

D

Step-by-step explanation:

<em>for </em><em>you </em><em>to </em><em>find </em><em>x </em><em>you </em><em>first </em><em>have </em><em>to </em><em>find </em><em>the </em><em>adjacent</em><em> </em><em>of </em><em>the </em><em>4</em><em>5</em><em>°</em><em> </em><em>angle </em><em>you </em><em>can </em><em>do </em><em>that </em><em>by </em><em>using</em><em> </em><em>the </em><em>other </em><em>triangle.</em><em>u</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>the </em><em>sin </em><em>ratio</em>

<em>sin60=</em><em>opposite</em><em>/</em><em>hypotenuse</em>

<em>sin60=</em><em>a/</em><em>7</em><em>√</em><em>3</em>

<em>a</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>then </em><em>after </em><em>you </em><em>have </em><em>found</em><em> </em><em>the </em><em>adjacent</em><em> </em><em>you </em><em>can </em><em>use </em><em>the </em><em>cos </em><em>ratio</em>

<em>cos45=</em><em>adjacent/</em><em>hypotenuse</em>

<em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>x</em>

<em>cos45x/</em><em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>cos45</em>

<em>x=</em><em>1</em><em>4</em><em>.</em><em>8</em><em>4</em><em>9</em>

<em>which </em><em>is </em><em>the </em><em>same </em><em>as </em><em>2</em><em>1</em><em>√</em><em>2</em><em> </em><em>over </em><em>2</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

5 0
3 years ago
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9-8x=35 explain please
ANEK [815]

9 - 8x = 35

subtract 9 from both sides

-8x = 26

divide both sides by -8

x= -26/8

you can simplify this to -13/4

7 0
3 years ago
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Need help pronto
algol13

Answer:

35 hours and 45 minutes

Step-by-step explanation:

5 0
3 years ago
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The sun produces 3.9 ⋅ 10 to the 33th power ergs of radiant energy per second. How many ergs of radiant energy does the sun prod
arlik [135]
So the sun produces 3.9x10³³/ second

Using this ratio (3.9x10³³/ second) we can use the porpotions to calculate time taken (T) to produce 1.55x10⁷.

\frac{3.9(10^3) ergs}{1 second} =  \frac{1.55(10^7)ergs}{T}

Then isolate T and find the time

\frac{T3.9(10^3)ergs}{1 second} = {1.55(10^7)ergs
T3.9(10^3)ergs = ({1.55(10^7)ergs)seconds
T =  \frac{(1.55(10^7)ergs)seconds}{3.9(10^3)ergs}
T =  \frac{(1.55(10^7)seconds}{3.9(10^3)}
T = \frac{1.55}{3.9}(10^4)seconds
T = 0.397(10^4)seconds
T = 3.97(10^-^1)(10^4)seconds
T = 3.97(10^3)seconds

Thus it took 3.97x10³ seconds for 1.55x10⁷. of ergs to be produced
Hope that helped and if it did, a Brainliest rating would be much appreciated


6 0
3 years ago
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