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3 years ago

6

A motorist drives from home to his office .The distance between his home and office is 32.27 km.After driving 15.65 km,he stoppe

d at a petrol station .How much further does he have to drive before he arrives at his office ?Give your answer to the nearest kilometre .

1 answer:

Marianna [84]3 years ago

6 0

16.62 if rounded 17km

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erastovalidia [21]

Answer: $\dfrac{2x}{3 + x^2}$

Step-by-step explanation:

We know the property of derivative: $\dfrac{d}{dx}(\log (x))=\dfrac{1}{x}$

Given function : $y=\ln(3 + x^2)$

Differentiate both sides with respect to x , we get

$\dfrac{dy}{dx}=\dfrac{d}{dx}(\ln(3 + x^2))$

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot\dfrac{d}{dx}(3 + x^2)$ [By Chain rule]

$\Rightarrow\ \dfrac{dy}{dx}=\dfrac{1}{3 + x^2}\cdot(0+2x)$

[Since $\dfrac{d}{dx}(a)=0$ , where a is scalar and $\dfrac{d}{dx}(x^n)=n(x)^{n-1}$ ]

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Hence, the derivative of the given function is $\dfrac{2x}{3 + x^2}$ .

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3 years ago

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Inessa05 [86]

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3 years ago

Roberto purchased airline tickets for his family of 4. The tickets cost $1,250.The airline also charged a luggage fee,bringing t

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3 years ago

Read 2 more answers

ivann1987 [24]

9514 1404 393

Answer:

large: 55 lb
small: 30 lb

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...

x + y = 85 . . . . . combined weight of a large and small box

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We can subtract 50 times the first equation from the second to find the weight of a large box.

(70x +50y) -50(x +y) = (5350) -50(85)

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x = 55 . . . . . . . divide by 20

Using this in the first equation, we can find the weight of a small box.

55 +y = 85

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3 years ago

Explain how to simplify this complex fraction. 330pages/3/4hour.

meriva

Answer:
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= (330 × 4) / (3 × 1)

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<span>= 440

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3 years ago