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4 years ago

6

A motorist drives from home to his office .The distance between his home and office is 32.27 km.After driving 15.65 km,he stoppe

d at a petrol station .How much further does he have to drive before he arrives at his office ?Give your answer to the nearest kilometre .

1 answer:

Marianna [84]4 years ago

6 0

16.62 if rounded 17km

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

<em>a. The system of equations that models the situation is....</em>

<em> $0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40$ </em>

<em>b. The solution to the system: x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0

3 years ago

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviati

Irina-Kira [14]

The mean absolute deviation for the number of hours students practiced the violin is 6.4.

<h3>What is the mean absolute deviation?</h3>

The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.

Given

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.

The given data set is;

45, 38, 52, 58, 42

Mean Deviation = Σ|x − μ|/N.

μ = mean, and N = total number of values

|x − μ| = |45 − 47| = 2

|38− 47| = 9

|52− 47| = 5

|58− 47| = 11

|42− 47| = 5

The mean absolute deviation for the number of hours students practiced the violin is;

$\rm Mean =\dfrac{2+9+5+11+5}{5}\\\\Mean=\dfrac{32}{5}\\\\Mean = 6.4$

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.

To know more about mean value click the link given below.

brainly.com/question/5003198

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2 years ago

Factor the expression <br> 36x + 27 using the GCF.

laila [671]

Answer:

9(4x+3) :)

Step-by-step explanation:

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3 years ago

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Multiply (2x^3 + 1)(5x^2 +4) and write your result in simplest form.

tatyana61 [14]

(2x^3)*(5x^2)+(2x^3)*(4)+(1)*(5x^2)+(1)*(4)
10x^5+8x^3+5x^2+4

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3 years ago

Solve (x - 2 < 5) ∩ (x + 7 > 6).

hoa [83]

Answer:

c2

Step-by-step explanation:

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2 years ago